The Japanese 5 yen coin has a hole in the middle. The diameter of the coin is 22 mm and the diameter of the hole is 5 mm. What is the difference between the outer edge and the inner edge of the coin? If necessary, round your answer to the nearest tenth.

360.3 mm²

Step-by-step explanation:

the difference between the outer edge and the inner edge of the coin is the area of the coin - the area of the hole.

The formula for determining the area of a circle is expressed as

Area = πr²

Where

r represents the radius of the circle.

π is a constant whose value is 3.14

Considering the coin,

diameter = 22 mm

Radius = diameter/2 = 22/2 = 11 mm

Area = 3.14 × 11² = 379.94 mm²

Considering the hole,

diameter = 5 mm

Radius = 5/2 = 2.5 mm

Area = 3.14 × 2.5² = 19.625 mm²

The difference between the outer edge and the inner edge of the coin is

379.94 - 19.625 = 360.3 mm²

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

the answer is (-4,-4)

hope this ! : d