The lengths of corresponding sides of two squares are in the ratio of 3:1. If the area of the larger square exceeds the area of the smaller square by 63 in.², find the area of the smaller square

The area of the smaller square is 7.875 square inches

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Remember that all the squares are similar

Let

z ----> the scale factor

x ---> the area of the larger square

y ---> the area of the smaller square

so

we have

---> scale factor

substitute

----> equation A

That means---> the area of the larger square is 9 times greater than the area of the smaller square

The area of the larger square exceeds the area of the smaller square by 63 in.²

so

----> equation B

Equate equation A and equation B

solve for y

therefore

The area of the smaller square is 7.875 square inches

89

step-by-step explanation:

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: