Does the point (1, radical 7) lie on the circle shown? Explain. Yes, the distance from (–2, 4) to (–2, 0) is 4 units. Yes, the distance from (–2, 0) to (1, ) is 4 units. No, the distance from (–2, 0) to (1, ) is not 4 units. No, the distance from (–2, 4) to (1, ) is not 4 units.

Yes,the distance from (-2,0) to is 4 units

Step-by-step explanation:

We are given that

Center of circle=(-2,0)

Let point P(

We have to find that ( lies on the circle or not.

Distance formula:

Using the formula

Distance between Center (-2,0) and (-2,4)=Radius of circle=R

units

Distance between (-2,0) and (1,)=units

Distance between point P() and center (-2,0)=Radius of circle

Hence, the point P lies on the circle.

Yes,the distance from (-2,0) to is 4 units

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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