NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6. In an earlier study, the population proportion was estimated to be 0.4. How large a sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 98% confidence level with an error of at most 0.04

The sample size is = 814(approximately)

Step-by-step explanation:

Given -

Population proportion = 0.4

Confidence interval = 98

1 -  Confidence interval = 1 - .98

=  .02

 = .001

= .04

Let sample size = n

.04 =

For 98 level of confidence, z = 2.33

.04 =

(Squaring both side)

=

n =

n = 814.33

Approximately n =814

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

step-by-step explanation:

your answer is a