Find two numbers whose sum is 0 and who's difference is 8

Sum and Difference of Numbers

The two numbers are +4 and -4 whose sum is 0 and difference is 8

Step-by-step explanation:

Let the two numbers be x and y .

Then

x + y = 0; (1)

and

x - y = 8; (2)

Adding the two equation,

x + y = 0;

x - y = 8;

2 × x = 8

⇒ x = 8/2

⇒ x = +4

Subtracting (2) from (1)

⇒ 2 × y = -8

⇒ y = -4

Hence, the two numbers are +4 and -4 whose sum is 0 and difference is 8

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐