(-9q^3+-8q) + (3q^2-q-6q^3) I need to find the sum

-3q(4q^2+q+3)

Step-by-step explanation:

To solve this question we will have to open the bracket first

So let's solve

(-9q^3+(-8q)+(3q^2-q-6q^3)

Open the bracket first

(-9q^3-8q)+3q^2-q-6q^3

-9q^3-8q+3q^2-q-6q^3

Let's collect like terms

-9q^3-6q^3+3q^2-8q-q

-12q^3+3q^2-9q

We can actually factorise

-3q(4q^2+q+3)

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.