Find the minimum value of the parabola y=x^2+x

Step-by-step explanation:

The vertex of the parabola represents the mimimum value. A no calculus method of finding is as follows: Consider y = x^2 + 3x + 1, where a = 1 and b= 3. the x- co-ordinate is equal to -b/2a which equals -3/2. to find the y co-ordinate: y = (-3/2)^2 -3(3/2) + 1. y = 9/4 -9/2 + 1. y = -5/4. The minimum value (-5/4) is found at (-3/2, -5/4)