Tenesha is trying to draw a parallelogram and find its area using the two line segments shown. On a coordinate plane, 2 line segments are formed by points (1, 5), (5, 2), (12, 2). She begins by finding the missing vertex on the graph to be point (9, 5). Then she calculates the area of the parallelogram. What errors did she make? Check all that apply.

The missing vertex is not (9,5) it is rather (8,5)

Step-by-step explanation:

We cannot see Tenesha's solution steps, so we cannot identify her mistakes.

Moreover we cannot see the options.

However, the mistake we can spot with the available information is that, the fourth vertex of a parallelogram with vertex (1, 5), (5, 2), (12, 2) is not (9,5).

The two adjacent horizontal vertices are:

(5,2) and (12,2).

The distance between them is |12-5|=7.

Since the opposite sides of a parrlallelogram are congruent, the other horizontal vertex for (1,5) is (1+7,5), which is (1,5)

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.