Given 1+cosx\sinx+sinx\1+cosx=4, find a numerical value of one trigonometric function of x.

Option d.

Step-by-step explanation:

The complete question is

Given (1+cosx)/(sinx) + (sinx)/(1+cosx) =4, find a numerical value of one trigonometric function of x.

a. tanx=2

b. sinx=2

c. tanx=1/2

d. sinx=1/2

we have

Find the common denominator and adds the fractions

Expanded the numerator

Remember that

----> trigonometric identity

substitute

Factor 2 in the numerator

Simplify

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

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step-by-step explanation: