The area of a playground is 336 yd2. the width of the playground is 5 yd longer than its length. find the length and width of the playground

L=16
W=21

Set up a systems of equations: 
x=length 
y=width 

xy=336
x+5=y

Use substitution to solve: 
x(x+5)=336
x^2+5x=336 

Solve using factoring: 
x^2+5x-336=0
(x-16)(x+21)=0
x=16 and x= -21 
Since length can't be negative, l=16 

To find width, plug length into the first equation: 
(16)y=336
y=21 

So...
L=16
W=21