Which of the following are possible equations of a parabola that has no real solutions and opens downward?

y > = -(x + 4)^2- 2
y > = -(x + 4)^2 + 2
y > = -x^2 - 2
y > = (x - 4)^2 + 2
y > = -(x - 4)^2- 2

Step-by-step explanation:

A vertex form equation of a parabola is of the form

with vertex at (h,k).

If a parabola opens downwards, then a<0.

If the vertex of such parabola is below the x-axis, then it has no real solution, because it will not intersect the x-axis.

has vertex at (-4,-2), which is below x-axis.

has vertex at (-4,2)--->above x-axis

vertex at (4,-2) ---> below x-axis

(0,-2)----> below x-axis

step-by-step explanation:

coldest temperature they recorded add me europa2433

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all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: