Trapezoid jklm is shown on the coordinate plane below:

trapezoid jklm on the coordinate plane with ordered pairs at j negative 6, 5, at k negative 3, 5, at l negative 1, 2, at m negative 8, 2.

if trapezoid jklm is translated according to the rule (x, y) → (x + 2, y − 6), what are the coordinates of point l'?

(1, −4)
(−4, −1)
(−7, 4)
(0, 7)

 the correct option is

(A) (1, -4).

Step-by-step explanation:  The trapezoid JKLM is shown on the co-ordinate plane.

The co-ordinates of the vertices of trapezoid JKLM are J(-6, 5), K(-3, 5), L(-1, 2) and M(-8, 2).

The trapezoid JKLM is translated according to the following rule :

(x, y) → (x + 2, y − 6).

We are to find the co-ordinates of point L'

Since the co-ordinates of point L are (-1, 2), so the co-ordinates of the point L' will be

L(-1, 2)  →   L'(-1+2, 2-6)= L'(1, -4).

Thus, the co-ordinates of point L' are (1, -4).

Option (A) is CORRECT.

x+y = 29, 5x + 2y = 100

step-by-step explanation:

i'm guessing it was a multiple first option was the correct answer

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value