PLS HELP IM DOING THIS NOW and IDU, Students from Williams Middle School are also recycling aluminum cans. The data for the numbers of cans brought in each school day for a month were divided by quartiles and summarized in the box plot. Use the drop-down menus to choose the median, interquartile range, and range.
>Median:
>Interquartile range:
>Range:

Given:

Students from Williams Middle School are also recycling aluminum cans. The data for the numbers of cans brought in each school day for a month were divided by quartiles and summarized in the box plot.

We need to determine the Median, Interquartile range and Range.

Median:

The median is the middle value of the given set of data.

From the box plot, it is obvious that the median line is at 18.

Thus, Median = 18

Hence, the value of the median is 18.

Interquartile range:

The interquartile range is can be determined by finding the difference between the ends of the box in the box plot.

From the box plot, we have;

Interquartile range = 20 -16

Interquartile range = 4

Hence, the value of the interquartile range is 4.

Range:

The range can be determined by subtracting the highest and the lowest value in the given set of data.

From the box plot, the range can be determined by subtracting the ends of the line.

Thus, we have;

Range = 28 - 10

Range = 18

Hence, the value of the range is 18.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

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step-by-step explanation:

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