A particular fruit's weights are normally distributed, with a mean of 426 grams and a standard deviation of 37 grams. If you pick 9 fruit at random, what is the probability that their mean weight will be between 413 grams and 464 grams. Round to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 2 decimal places are accepted.

Probability that their mean weight will be between 413 grams and 464 grams is 0.8521.

Step-by-step explanation:

We are given that a particular fruit's weights are normally distributed, with a mean of 426 grams and a standard deviation of 37 grams.

Also, you pick 9 fruit at random.

Let = sample mean weight

The z-score probability distribution for sample mean is given by;

              Z =  ~ N(0,1)

where, = population mean weight = 426 grams

             = population standard deviation = 37 grams

            n = sample of fruits = 9

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the mean weight of 9 fruits picked at random will be between 413 grams and 464 grams is given by = P(413 grams < < 464 grams) = P( < 464 grams) - P( 413 grams)

 P( < 464 grams) = P( < ) = P(Z < 3.08) = 0.99896

 P( 413 grams) = P( ) = P(Z -1.05) = 1 - P(Z < 1.05)

                                                               = 1 - 0.85314 = 0.14686

{Now, in the z table the P(Z  x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 3.08 and x = 1.05 in the z table which has an area of 0.99896 and 0.85314 respectively.}

Therefore, P(413 grams < < 464 grams) = 0.99896 - 0.14686 = 0.8521

Hence, the probability that their mean weight will be between 413 grams and 464 grams is 0.8521.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3