Margaret is planning a wedding reception. She wants to spend less than her budget of 5,676, and margaret has already spent 2,652. The meal price per guest is 28. How many guests, x, can margaret invite to the reception and stay under budget?

The answer to your question is 108 guests.

Step-by-step explanation:

Data

Budget = $5676

She has spent = $2652

price per guest = $28

number of guests = x

Process

1.- Determine the quantity of money available.

   Money available = 5676 - 2652

                               = $3024

2.- Divide the money available by the price per guest

  Number of guests = $3024/$28

  Number of guests = 108

3.- Conclusion

She can invite at most 108 guests

she can invite less than 108 guests to the reception and stay under budget.

Step-by-step explanation:

Let x represent the number of guests that she can invite.

The meal price per guest is 28. It means that the meal price for x guests would be 28x.

She wants to spend less than her budget of 5,676, and Margaret has already spent 2,652. It means that the amount she has left to spend is

5676 - 2652 = 3024

Since she wants to spend less that 3024, then

28x < 3024

x < 3024/28

x < 108

vbbv

step-by-step explanation:

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm