subject
Mathematics, 04.04.2020 08:30 mandoux

EXAMPLE 2 Find a formula for the general term of the sequence 2 5 , − 3 25 , 4 125 , − 5 625 , 6 3125 , assuming that the pattern of the first few terms continues. SOLUTION We are given that a1 = 2 5 a2 = − 3 25 a3 = 4 125 a4 = − 5 625 a5 = 6 3125 . Notice that the numerators of these fractions start with 2 and increase by whenever we go to the next term. The second term has numerator 3, the third term has numerator 4; in general, the nth term will have numerator . The denominators are powers of , so an has denominator . The signs of the terms are alternately positive and negative so we need to multiply by a power of −1. Here we want to start with a positive term and so we use (−1)n − 1 or (−1)n + 1. Therefore, an = (−1)n − 1 · .

ansver
Answers: 3

Another question on Mathematics

question
Mathematics, 20.06.2019 18:04
Me find the measure to side c and the process to solve the problem you appreciate it : )
Answers: 1
question
Mathematics, 21.06.2019 16:00
Graph the equation by plotting point x=2
Answers: 1
question
Mathematics, 21.06.2019 17:30
What number should be added to the expression x^2+3x+ in order to create a perfect square trinomial? 3/2 3 9/4 9
Answers: 1
question
Mathematics, 21.06.2019 19:20
Which number line represents the solution set for the inequality - x 24?
Answers: 3
You know the right answer?
EXAMPLE 2 Find a formula for the general term of the sequence 2 5 , − 3 25 , 4 125 , − 5 625 , 6 312...
Questions
question
History, 20.03.2021 06:40
question
Mathematics, 20.03.2021 06:40
question
Physics, 20.03.2021 06:40
question
Mathematics, 20.03.2021 06:40
question
Mathematics, 20.03.2021 06:40
question
Biology, 20.03.2021 06:40
question
Chemistry, 20.03.2021 06:40
question
Biology, 20.03.2021 06:40
Questions on the website: 13722367