What is the equation of the line passing through the pair of points. Write the equation in slope-intercept form. (9,5) and (5,9)

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

To find the slope(m), use the slope formula:

     And substitute/plug in the two points

(5, 9) = (x₁, y₁)

(9, 5) = (x₂, y₂)

m = -1        Now that you know the slope, plug it into the equation

y = mx + b

y = -1x + b   or   y = -x + b    To find b, plug in either one of the points into the equation, it doesn't matter which you use. I will use (5, 9)

9 = -(5) + b        Add 5 on both sides to get "b" by itself

9 + 5 = -5 + 5 + b

14 = b

y = -x + 14

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐