Whats the equation of a line with slope 3/5 that passes through the point (15,8)

y=3/5x-1

Step-by-step explanation:

The formula you need to find this would be

(y-y1)=m(x-x1)

The y1 is your y point.

The x1 is your x point.

m is your slope.

Start by plugging in your numbers that they provide you.

(y-8)=3/5(x-15)

Now you need to distribute the slope to the terms inside the parenthesis next to it.

3/5(x)=3/5x

3/5(-15)= -9       Now you put those back into the equation.

(y-8)=3/5x-9

At this point you can get rid of the parenthesis around the y-8 since it is basically saying to take the term times 1.

To get y alone we not need to add 8 to both sides.

y-8=3/5x-9

+8          +8

y=3/5x-1