A coin is tossed two times, then a month of the year is randomly selected. What is the probability of getting tails each time, and a month that starts with the letter J? I got 1/8 is that correct if not what’s the answer

1/16

Step-by-step explanation:

Given a fair coin, the probability of getting tails on any one toss =

P(tails) = 1/2

if a coin is tossed twice and  we get tails both times,

P( 2 tails on 2 consecutive tosses) = (1/2)(1/2) = 1/4

Total number of months = 12 months

Months that start with J = January, June, July = 3 months

P(selecting months that start with J) = 3/12 = 1/4

Hence the probability of tossing 2 consecutive tails then selecting a month that starts with J

= (1/4) x (1/4)

= 1/16

5+2x=a

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