An arrow is shot vertically upward at a rate of 280 feet per second. Use the projectile formula
h = −16t2 + v0t
to determine at what time t (in seconds) the height of the arrow will be 200 feet.

Time is 16.75 seconds when the arrow reaches 200 ft

Step-by-step explanation:

Height = 200 ft

v = 280 ft/s

Projectile formula, h = -16t² + vt

⇒ 200 = -16t² + 280t

⇒ 16t² - 280t + 200 = 0

⇒ 2t² - 35t + 25 = 0 (dividing by common factor 8)

Using quadratic formula to find t

t = (35 ±√35² - 4×2×25)/2×2

t = (35 ±√1225 - 200)4 = 35 ± 32.02/4

∴ t = 67/4 or 3/4  

t = 16.75 seconds

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

where is the diagram? shown below where? ?

step-by-step explanation: