427- one digit is right but in the wrong place
490- one digit is right in its place
032- two digits are right but both in the wrong place
156- all digits are wrong
593-one dit is right but in the wrong place

Can you answer it with 3 digit number

??? Like a code for lock

370

Step-by-step explanation:

Let the code be: abc

Clues:

⇒ Starting with clue 4 and discarding 1,5 and 6

⇒ Clue 2 and 5 ⇒ discarding 9 since contradicting statements, it can't be in the second place as it is wrong according to other statement

⇒ Clue 5 and 3 ⇒ 3 is left as correct digit and goes to first place to replace a.

⇒ Clue 1 and 2 ⇒ discarding 4 as it can't be right and wrong same time

⇒ Clue 2 ⇒ since other 2 digits are discarded, 0 left as correct digit and it goes to third place to replace c.

⇒ Clue 1 and 3⇒ digit 2 is discarded, as digits 0 and 3 chosen, we have left with digit 7 which goes to second place to replace b.

So the code is: 370

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice