Find the area of the following polygon:

Given:

ABCD is a quadrilateral

AC = 12, DE = 4 and FB = 5

To find:

The area of the polygon.

Solution:

AC bisects the quadrilateral into two triangles.

Area of triangle:

Area of triangle DAC:

Area of triangle DAC = 24 square units.

Area of triangle BAC:

Area of triangle BAC = 30 square units.

Area of polygon = Area of triangle DAC + Area of triangle BAC

                           = 24 square units + 30 square units

                           = 54 square units

The area of the polygon is 54 square units.

true? is that what you're asking or do you mean something else?