In a chemistry class 7 Liters of a 4% Iodide solution must be mixed with a 10% solution to get a 6% solution how many liters of a 10% solution are needed

The number of liters where 10% of solutions needed should be 3.5 liters.

Given that,

7 Liters of a 4% solution should be mixed with a 10% solution.

So, that 6% solution could come.

Let us assume the number of liters be x.

So,

The following equation should be made:

Now Multiply it by 100

x = 3.5 liters

Therefore we can conclude that the number of liters where 10% of solutions needed should be 3.5 liters.

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3.5

Step-by-step explanation:

If x is the volume of 10% solution, and y is the volume of 6% solution, then:

x + 7 = y

0.10x + 0.04(7) = 0.06y

Solve the system of equations.

0.10x + 0.04(7) = 0.06(x + 7)

0.10x + 0.28 = 0.06x + 0.42

0.04x = 0.14

x = 3.5

3.5 liters of 10% solution is needed.

i will pick c put check it over to be sure

step-by-step explanation:

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50