1) Luis hizo una excursión de 20 km 75 hm 75 dam 250 m en tres etapas. En la primera recorrió 5 km 5hm, y en la segunda 1 km 50 dam más que en la anterior. a) ¿Cuánto recorrió en la tercera etapa? b) Expresa el resultado en metro

21500 m

Step-by-step explanation:

We will divide this point into four parts and we will pass it by the meter:

Total: (20 km * 1000 m / 1 km) + (75 hm * 100 m / 1 hm) + (75 dam * 10 m / 1 dam) + 250 m = 20000 m + 7500 m + 750 m + 250 m = 28500 m

First stage: (5 km * 1000 m / 1 km) + (5 hm * 100 m / 1 hm) = 5000 m + 500 m = 5500 m

Second stage: (1 km * 1000 m / 1 km) + (50 dam * 10 m / 1 dam) = 1000 m + 500 m = 1500 m

The value of the third stage would be the subtraction between the total and the first and second stage:

Third stage: 28500 m - 5500 m - 1500 m = 21.500 m

He traveled 21500 meters in the third stage

i think asking google will you get the answer to that question