Y=8x-2, find the equation of the line that is perpendicular to this line and passes through the point (-5, -6)

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be perpendicular, their slopes have to be negative reciprocals of each other (flip the sign +/- and the fraction/switch the numerator and the denominator)

For example:

Slope = -2 or        

Perpendicular line's slope:        (flip the sign from - to +, and flip the fraction)

Slope =

Perpendicular line's slope =  or  -3     (flip the sign from + to -, flip fraction)

y = 8x - 2    The slope is 8, so the perpendicular line's slope is .

Now that you know the slope, substitute/plug it into the equation:

y = mx + b

   To find b, plug in the point (-5, -6) into the equation, then isolate/get the variable "b" by itself

    (Two negative signs cancel each other out and become positive)

   Subtract 5/8 on both sides to get "b" by itself

    (To combine fractions, they need to have the same denominator, so multiply -6 by 8/8 so that they will have the same denominator)

= b      Now combine the fractions

6 on both sides and twelve on the top and the bottom

step-by-step explanation:

144.50

step-by-step explanation:

21.5 x 13.4=288.10 divide by 2