Acircle has a diameter with endpoints of (-3, 8) and (7, 4). what is the center of the circle?

(10, 12)
(5, 12)
(2, 6)

The center of the circle is expressed as (h,k) in the standard form  of equation. In this case, the diameter endpoints are (-3, 8) and (7, 4). Hence the circle center has coordinates which are the midpoints of the two points. 

x = (-3 + 7) /2  = 2
y = (8 + 4) /2 = 6 

hence the center of the circle is (2,6)