Four different objects are placed on a number line at 0. The chart describes the motion of each object.

Using the information in the chart, the distance and displacement of each object can be determined. Which object has a distance that is three times as great as its displacement?

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

35-60 students are taking math.

0,0

step-by-step explanation:

9987

step-by-step explanation: