You roll a six-sided number cube. What is
the probability that you will roll a number
greater than two?

1, 2, 3, 4, 5, 6

p greater than 2 = 4/6 = 2/3

p 2 or smaller and prime = 2/6 = 1/3

2/3 + 1/3 = 1

every single side of the cube is either greater than 2 or prime (two and one) so you simply will get the desired result in 100% of your rolls

Step-by-step explanation:

no of favourable cases, n(E) = 4

no of sample space, n(S) = 6

Probability that it will be rolled on the number greater than two, P(E) = n(E) / n(S) = 4/6 = 2/3

step-by-step explanation:

1. the cylinder is a. 54

2.   a.108 /

1. d.90

2. e. none of these (80)

3. a. 0

4. b. 6

5. e. none of these (10)

6. a. 5