A teacher gave her class two exams; 60% of the class passed the second exam, but only 48% of the
class passed both exams. What perdent of those who passed the second exam also passed the first
exam? (2 points)
O 80%
12%
30%
48%

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

a

step-by-step explanation:

u take $30 minus $24. the answer/original($30)

do you have a picture of the table