If Cos A >0, and Csc A < 0, what quadrant does A lie?

I don't know how to do this properly. I need the work to help

Quadrant IV.

Step-by-step explanation:

You need to remember that :

All trig ratios are positive in the Quadrant I.

Sine and csc are positive in Quadrant II.

Tan and cot are positive in Quadrant III.

Cos and sec are positive in Quadrant IV.

So if cos A > 0 ( ie positive) it is in either Quadrant I or IV.

Csc is <0 (negative) so it is in either Quadrant II or IV.

So if cos A > 0 and csc < 0 , A must be in Quadrant IV.

Hope this helps.

Feel free to ask questions if this is not entirely clear.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )