The angle of Inclination from the base of skyscraper A to the top of skyscraper B is approximately 11.9°. If Skyscraper B is 1424 feet tall, how far apart are the two skyscrapers? Assume
the bases of the two buildings are at the same elevation.
feet.
The distance from skyscraper A to skyscraper B is
(Round to two decimal places as needed.)

6757.36ft to 2dp

Step-by-step explanation:

For base distance there are different ways in trigonometry to find the base. For this finding we are given the height and opposite angle.

We can then calculate; using division 1424 /tan 11.9 =6757.36427ft

For slope we can find Sin(11.9°) x 1424 to find 293.63ft.

It shows, 293.63476 on the calculator so the answer is kept at 293.63ft= left to 2dp ( or 3524 inches) away

answer: 180

step-by-step explanation:

12-2=10

20-2=18

18x10=180