What net force will make a 5 kg bowling ball accelerate by 1.5 m/s square 2?

In pure translation or in roll without slip?

In pure translation, just use Fnet = m*a.  Fnet = 7.5 Newtons

In roll without slip it has effectively more inertia than 5 kilograms.  The effective inertia can be found as:

m_effective = m + I/r^2

For a uniform solid sphere, I = 2/5*m*r^2

So m_effective = 7/5*m

To make a 5 kg bowling ball accelerate at 1.5 m/s^2 in roll without slip, it requires Fnet = 10.5 Newtons, and this ASSUMES that all forces causing the net force on it have lines of action through its center of mass (most common case).

i hope this is what ur looking for

step-by-step explanation:

1. practice, practice & more practice

2. review errors

3. master the key concepts

do not try to memorise the processes.

4. understand your doubts.

5. create a distraction free study environment

6. create a mathematical dictionary

7. apply maths to real world problems.

entering that problem on the tube might get you an answer