I have X, I just need Y.

Help would be much appreciated as I am pretty rusty on law of cosines

X= 9.32

Y=?

I'm getting x = 9.3223 which rounds to 9.32. Nice work.

Once you know the value of x, you can use the law of sines to find the value of y

sin(A)/a = sin(B)/b

sin(y)/7 = sin(70)/x

sin(y)/7 = sin(70)/9.3223

sin(y) = 7*(sin(70)/9.3223)

sin(y) = 0.70560358983312

y = arcsin(0.70560358983312)

y = 44.8783278056846

If you must use the law of cosines, then here's how you could do it

c^2 = a^2 + b^2 - 2*a*b*cos(C)

7^2 = x^2 + 9^2 - 2*x*9*cos(y)

7^2 = (9.3223)^2 + 9^2 - 2*9.3223*9*cos(y)

49 = 86.90527729+81-167.8014cos(y)

49 = 167.90527729-167.8014cos(y)

-167.8014cos(y) = 49-167.90527729

-167.8014cos(y) = -118.90527729

cos(y) = -118.90527729/(-167.8014)

cos(y) = 0.708607182598

y = arccos(0.708607182598)

y = 44.8782954209662 ... this is slightly different from before due to rounding error

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.

it could be 1,3 and more others to create a cylinder.

step-by-step explanation: