A rectangular tank that is 4 feet long, 5 feet wide and 15 feet deep is filled with a heavy liquid that weighs 110 pounds per cubic foot. In each part below, assume that the tank is initially full. Your answers must include the correct units. (You may enter lbf or lb*ft for ft-lb.)

How much work is done pumping all of the liquid out over the top of the tank?

247500 J

Step-by-step explanation:

We are given that

Length,l=4 feet

Width,b=5 feet

Height,h=15 feet

Weigh,w=110

We have to find the work done in pumping all of the liquid out over the top of the tank.

Area of cross-section,A=

Force increment,

Work increment ,

Total work done,W=

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

i would you but i don't under stand the qustion

step-by-step explanation: