Which exponential function has an initial value of 3?
A 2-column table has 2 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f (x) with entries negative 3.938, negative 3.75, negative 3, 0, 12.

f (x) = one-third (9) Superscript x

On a coordinate plane, an exponential function crosses the y-axis at (0, 3).

f (x) = (3) Superscript x

C

Step-by-step explanation:

1,3.5

Step-by-step explanation:

just did it in Edge

597

step-by-step explanation:

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb