What is the probability that Bo, Colleen, Jeff, and Rohini win the first, second, third, and fourth prizes, respectively, in a drawing if 48 people enter a contest and winning more than one prize is allowed

1/4669920

Step-by-step explanation:

First if all, when repetition is mot allowed, we use Permutation to get the number of possible outcomes as follows;

P(n, r) = n!/(n - r)!

Now, the order is important since the first, second, third and fourth prizes are different.

Thus, we need to define the Permutation.

We need to select 4 winners of the 48 people.

Thus, n = 48 and r = 4

Thus;

P(48,4) = 48!/(48 - 4)!

P(48,4) = 4669920

Now, probability is the number of favourable outcomes divided by number of possible outcomes

Thus,

Probability = 1/4669920

third choice down

step-by-step explanation:

the first inequality is based on the number of adults and campers, and the second inequality is based on the cost of feeding both the adult and the camper.

we know that there is room for 525 people max.   it's ok to have less than 525, but it's not ok to have more than 525, so the inequality is less than or equal to.   the number combination of adults (x) and campers (y) cannot exceed this 525 max.   therefore:

x + y ≤ 525

now we talk about cost.   it costs $9 to feed one adult, so depending upon the number of adults you have (x) depends upon how much it will cost to feed that number of adults.   same with the campers, who cost $5 to feed.   the adults can be represented by 9x and the campers can be represented by 5y.   since the budget cannot exceed 1,200, the second inequality is:

9x + 5y ≤ 1200