*Two congruent rhombi share the point of intersection of their diagonals. Shorter diagonals are perpendicular to each other. Prove that the line joining the point of intersection of the diagonals and the midpoint of the side of one rhombus is perpendicular to a side of the other rhombus.

hi there!

the answer will be d: 2

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4

table a is wierd

step-by-step explanation:

6*f

step-by-step explanation:

graph using a few selected

x         y

-1       15

0         6

1         2.4

2       0.96