The height of a cylindrical tank is 9.5 feet. The diameter of this tank 1.5 feet longer than the height. The tank was holding water at full capacity, but someone consumed one-seventh of the water. Which is closest to the volume of the remaining water in the tank?

774 cubic feet of water is remaining in the tank

Step-by-step explanation:

In this question, we are asked to calculate the remaining volume in cylindrical tank given that someone consumed 1/7 of its capacity.

Firstly, we need to calculate the capacity in terms of volume of the cylindrical tank.

Since it is a cylinder, we will use the volume of a cylinder.

Mathematically, volume of a cylinder V ;

V = pi * r^2 * h

Where h represents height; 9.5 feet in this case

radius r is diameter d/2 ; we were made to know that diameter of the tank is 1.5 feet longer than the tank. This means the diameter of the tank will be 9.5 + 1.5 = 11 feet. The radius of the tank is thus 11/2 = 5.5 feet

The volume V is thus;

V= 22/7 * 5.5^2 * 9.5

V = 903 cubic feet approximately

Since 1/7 of the tank is consumed, what will remain will be 6/7

This means what is remaking will be 6/7 * 903 = 774 cubic feet

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet