Stewart, ch14.2, find the limit. Since y = 0 for all points on this path, then we have Similarly, approaching along the y-axis yields a limit equal to 0. Since these two limits are the same, we will examine another approach path. Approach (0, 0) along the curve y = x^2. When x is positive, we have When x is negative, we haveSimilarly, approaching along the y-axis yields a limit equal to 0. Since these two limits are the same, we will examine another approach path. Approach (0, 0) along the curve y = x2. When x is positive, we have lim (x, y) → (0, 0) xy x2 + y2 = lim x → 0 x x2 + x4 = lim x → 0 x2 . When x is negative, we have lim (x, y) → (0, 0) xy x2 + y2 = lim x → 0 x x2 + x4 = lim x → 0 x2 − 0 .

To fill in the boxes, use these rules

In the second expression, y=x².

In the third expression, y=x

Step-by-step explanation:

Since y = 0 for all points on this path, then we have

Similarly, approaching along the y-axis yields a limit equal to 0. Since these two limits are the same, we will examine another approach path. Approach (0, 0) along the curve .

When x is positive, we have:

From the equality above:

In the second expression, y=x².

In the third expression, y=x

When x is negative, we have,

answer: finding the extract measurements and knowing the points

step-by-step explanation:

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42