) Consider the circle of radius 2 centered on the x-axis at the point (5, 0). If you rotate this circle around the y-axis, you get a torus (a. k.a a doughnut). Find the surface area of the torus using an integral.

236.87 Square Units

Step-By-Step Explanation

Consider a torus generated by the rotation of the circle about the y-axis  given below.

The perimeter of its cross section is 2\pi r. When it involves the y-axis:

Its total surface area:

For a circle radius 2 centered on the x-axis at the point (5, 0).

r=2. x=5, y=0

5-R=2

R=5-2=3

Therefore, the total Surface Area is:

step-by-step explanation:

i think you should think about the question and not look online.

50.6

step-by-step explanation: