Which of the following would be equivalent to 9^2 times 9^6

9^2 × 9^6=9^10/9^2

When multiplying exponents, if the bases are the same you add the exponents.

9^2 × 9^6 = 9^(2+6)=9^8

When dividing exponents, I'd the bases are the same you subtract the bottom exponent from the top.

9^10/9^2=9^(10-2)=9^8

9^8=9^8

Solution: 9^10 over 9^2

Step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92