A rocket in the shape of acone is attached to a cylinder with the same base radius the cone has aslant height of 15m the cylinder has abase diameter of 12m and a height of 42m find the total surface area of the rocket

the total surface area of the rocket: 1978.2    

Step-by-step explanation:

Given that :

So the surface area of a a cone with about the base area because it is attached to a cylinder:

= π*r*l = 3.14*6*15 = 282.6

The area of the cylinder is: 2*π*r*h+pi* (without the top part of it)

= 2*3.14*6*42 + 3.14*

= 1695.6  

At the end, the total surface area of the rocket:

1695.6  + 282.6 = 1978.2    

a. -0.3 > -0.33

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option