(2) The ceiling of Katie’s living room is a square that is 25 ft long on each side. To decorate for a party, she plans to hang crepe paper around the perimeter of the ceiling and then from each corner to the opposite corner. (just 2 diagonals) Katie can buy rolls that each contain 30 ft of crepe paper. What is the minimum number of rolls she should buy?
(assume the crepe paper is hung flush with the wall and ceiling)
Use special right triangles to find the answer. Using any other method will result is 0 points. Show ALL work.

the answer is..
25^2 + 25^2 = c^2 625 + 625 = c^2 c^2 = 1250 c = 35.4
25 + 25 + 25 + 25 + 35.4 + 35.4 = 170.8 (round up to 180) 180 / 30 = 6 rolls
The minimum number of rolls she should buy is 6 rolls

are you an artist's daughter? cuz dang you a fine piece of art, girl.

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

i believe that the answer is

b. y-1=-2(x-4)

hope this !