Mathematics, 07.04.2020 23:01 dward5823
Let X be from a geometric distribution with probability of success p. Given that P(X > y) = (1 p)y for any positive integer y. Show that for positive integers a and b, P(X > a + X > a) = P(X > b).
Answers: 3
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Parabolas y=β2x^2 and y=2x^2 +k intersect at points a and b that are in the third and the fourth quadrants respectively. find k if length of the segment ab is 5.
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Let X be from a geometric distribution with probability of success p. Given that P(X > y) = (1 p...
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