What is the equation of the line that is parallel to y-3x=2 and that passes through (6,1)?

• y=3x-17
• y=3x+19
• y=-3x+19
• y=-3x-17

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be parallel, they need to have the same slope.

y - 3x = 2      Add 3x on both sides to change the equation to slope-intercept form

y - 3x + 3x = 2 + 3x

y = 3x + 2   The slope is 3, so the parallel line's slope is also 3.

Now that you know the slope, substitute/plug it into the equation

y = mx + b

y = 3x + b    To find "b", plug in the point (6, 1) into the equation, then isolate/get the variable "b" by itself

1 = 3(6) + b  

1 = 18 + b     Subtract 18 on both sides to get "b" by itself

1 - 18 = 18 - 18 + b

-17 = b

y = 3x - 17    Your answer is the 1st option

y=3x-17

Step-by-step explanation:

You first get y by its and you do this by adding 3x to both sides of the equal sign. You should then get y=3x+2 and then to find the parallel line, the x should stay the same as the first equation so that takes out the -3x. Then you continue to draw the line down until you get a y-intercept which turns out to be 17. You also know that the y-intercept is going to be negative so that takes out the two 19's.