Two methods, A and B, are available for teaching a certain industrial skill. The failure rate is 35\% for A and 15\% for B. However, B is more expensive There hence is used only 40\% of the time, while A is used 60\% of the time. A worker is taught the skill by one of the methods but fails to learn it correctly. What is the probability that he was taught by method A?

Therefore the probability that he was taught by method A is 0.78.

Explanation:

The ratio of the number of favorable outcomes to the number of all possible outcomes.

If the events ,, ..... from a portion of a sample space S and A is any events of A, then

Given that,

There are two available method for teaching A and B.

The failure rate for A is 35%

That is P(F|A) =35%=0.35

The failure rate for B is 15%

That is P(F|A) =15%=0.15

A used 40% of the time.

P(A)=40%=0.40

B used 60% of the time.

P(A)=60%=0.60

To find P(A|F) , we use the Bayes's rule.

           =0.78

Therefore the probability that he was taught by method A is 0.78.

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )

answer:   y=2x-3

step-by-step explanation: