Mathematics, 08.04.2020 00:46 joho38

Do students from UF tend to spend less time texting than students at FSU? A random sample of 100 students was taken from both schools. Let muf be the population mean number of text messages sent per day at UF and let mufsu be the population mean number of text messages sent per day at FSU. How should we write the alternative hypothesis?A. Ha: mufsu - muf = 0 B. Ha: mufsu - muf > 0 C. Ha: mufsu - muf < 0 D. Ha: mufsu - muf does not equal 0

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Answer from: nevaehbell30

Option B ⇒ Ha: mufsu - muf > 0

Step-by-step explanation:

Based on the question given, the two categories of students under consideration are UF and FSU. Also, a sample of 100 students is taken from schools UF and FSU.

Let us denote the mean number of text messages sent per day at UF population by {\mu _f}μf , and denote the mean number of text messages sent per day at FSU population by {\mu _{fsu}}μfsu.

The alternative hypothesis for the difference of the means of the two populations must be stated since two populations are considered.

The alternative hypothesis is obtained as shown below:

From the information given, the UF students do take less time for texting in contrast to the FSU students. Since the UF students take less time than FSU, the difference between the mean of FSU and the mean of UF must be greater than zero.

The alternative hypothesis is,

{H_a}:{\mu _{fsu}} - {\mu _f} > 0Ha:μfsu−μf>0

Option B is the correct answer.

Answer from: Quest

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the lesson to learn here is that you shouldn't worry about points or rank. chances are, no matter how good an answer you may provide, your efforts will go mostly unnoticed unless you focus on the newest/most active questions that get posted.

Answer from: Quest

the system of inequity is

$y\leq -x+4$

$3y> x$

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

the solid line passing through the points (0,4) and (4,0).

$y-4=\frac{0-4}{4-0}(x-0)$

$y=-x+4$

the related equation of solid line is $y=-x+4$ .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

$y-0=\frac{0-1}{3-0}(x-0)$

$3y=x$

the related equation of dashed line is $3y=x$

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

$1=-0+4$

$1=4$

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be $\leq$ . the required inequality is