Write an equation of the line that passes through the points (-1, -2) and (2.4)

As eq of line passing through 2 points is

y-y1 = (y2-y1)/(x2-x1) ][ x -x1)

where (X1,y1)( x2, y2) denotes points lying on line

substitute (X1 ,y1) by( -1,-2) and (X2,y2) by( 2,4)

y+2 = 6/3 )( x+1)

y+2= 2x +2

y = 2x is required equation

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

my answer got deleted but it's a

step-by-step explanation: