The test statistic of zequals1.18 is obtained when testing the claim that pgreater than0.2. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of alphaequals0.05, should we reject Upper H 0 or should we fail to reject Upper H 0?

a) Right Tailed

b) p-value = 0.119

c) We fail to reject the Null Hypothesis()

Step-by-step explanation:

We have the following data:

Test Statistic = z = 1.18

Claim: p > 0.2

Part a) Type of Test

Remember that when there is Greater than, Lesser than or any synonymous word in the claim, this means that the test is one-tailed.

Since, the claim is that p is greater than 0.2, the hypothesis test will be Right Tailed.

Part b) P-value

We have to find the p-value for the given test statistic. Since, the test statistic is a z-value we will use z-table to find the p-value for this score. Since, this z-score is for claim that p is greater than 0.2, so we will find the p-value(probability) of score being above 1.18

The p-value of z being greater than 1.18 comes out to be 0.119. i.e.

p-value = 0.119

Part c) Decision

Calculated p-value is 0.119 and significance level = 0.05. The rule is:

Since, in this case our p-value is greater than the significance level, we fail to reject the null hypothesis ().

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

5   1/4   miles per hour

step-by-step explanation:

15   3/4 / 3 = 5   1/4