A digester contains 1,400 pounds of volatile matter under digestion. If 0.05 pound of new volatile solids can be added per day per pound of volatile matter under digestion, how many pounds of sludge solids can be added per day with a volatile content of 65 percent

The quantity of sludge solids is 107.69 pounds approximated to 108 pounds.

Step-by-step explanation:

Given:

Quantity of the volatile matter in the dig-ester = 1400 pounds

Volatile solids added per day per pound = 0.05

According to the question :

The added sludge solid in the dig-ester have 65% of volatile content.

Lets say that the total sludge added be 'x' pound.

⇒ The volatile content =

⇒ And sludge added  =

                                     = pounds

So,

⇒ The total quantity of sludge added:

⇒

⇒

⇒

⇒

⇒

⇒ pounds

The quantity of sludge solids that an be added per day with a volatile content of 65% is 107.69 approximated to 108 pounds.

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6